Answer: The frequency of a pendulum is directly related to the square root of the gravitational constant g. Gravitational force is reduced at high altitude, so the clock runs slower.
Does a pendulum clock go slow when taken to the top of high mountains?
On taking the pendulum to the top of a mountain, g will decrease, therefore, T will increase. The pendulum will take more time to complete one vibration, i.e., it will lose time.
When a pendulum clock is taken from plains to mountain it becomes slow but a wrist watch driven by spring remains unaffected explain?
When a clock controlled by a pendulum is taken from the plains to a mountain, it becomes slow but a wrist-watch controlled by a spring remains unaffected Due to decrease in the value of g at the mountain, the time period of the pendulum of the clock increases.
When pendulum clock is taken to mountain or mines the time period of oscillation?
The time period. Either sides of surface of earth g goes on decreasing, hence period increases.
What is the effect of the pendulum clock when it is taken to the mines?
looses time, length to be decreased.
Why does a pendulum clock gain time when taken from equator to the pole?
we know, acceleration due to gravity, g value at pole is greater than at equator. if it is taken to the poles g value increases. time period decreases so, the pendulum clock gains time. hence, if a pendulum clock gives correct time at the equator then, it gains time if it is taken to the poles.
When a pendulum clock is taken from sea level?
Solution for problem 7Q Chapter 11
Why? The equation for pendulum motion is: As we gain altitude the value of constant of gravity ‘g’ decreases. If a pendulum clock which is accurate at sea level is taken to high altitude it will slow down.
When a pendulum clock is taken to a mountain?
When the pendulum is taken to the top of mountain, the value of ‘g’ will decrease and hence time period will increase. As the pendulum takes more time to complete one vibration, it will lose time.
How does the time period get affected if a pendulum clock is taken to higher altitudes give the reason?
Will it gain or lose time? At high altitude, the value of acceleration due to gravity (g) is less than its value on the surface of the earth. So, it will take more time for the pendulum clock to complete one oscillation and hence, it will lose time. …
What is variation of a time period of a pendulum clock?
The second hand of the clock advances by one second that means second hand moves by two seconds when one oscillation is complete. A pendulum clock keeps proper time at temperature θ₀. If temperature is increased to θ (> θ₀) then due to linear expansion, length of pendulum and hence its time period will increase.
Why does the time period of a pendulum change when taken to the top of a mountain or deep in a mine will a clock keep correct time?
On the top of a mountain, the value of g is less than on the surface of the earth. As T∝1√g , so the time period of pendulum clock increses. It means pendulum clock will take more time to complete one oscillation, i.e., it will be loosing time.
How is the time period of a simple pendulum affected when the length is increased by four times?
Therefore we can say that time period is directly proportional to square root of length of the pendulum. Therefore as the length of the pendulum becomes four times, the time period becomes the 2 times.
When a person goes from the surface of the earth to deep in the mine, the acceleration due to gravity decreases. Therefore, time period of oscillation of the simple pendulum increases deep in the mine.
What is the work done by tension in the string of simple pendulum during one complete oscillation is equal to?
The work done by the tension in the string of a simple pendulum during one complete oscillation is equal to zero.
What will happen to the time period of a simple pendulum if it is taken deep inside a mine and why?
looses time, length to be decreased.
What are the factors on which time period of oscillation of simple pendulum does depends?
Answer: The time period of a simple pendulum depends upon the length of the pendulum, acceleration due to gravity and the temperature. it is directly proportional to the square root of length of pendulum (l) and inversely proportional to the square root of acceleration due to gravity (g).