# What is the effect of the pendulum clock when it is taken to the mines?

Contents

looses time, length to be decreased.

## When a pendulum clock is taken inside a mine?

The time period. Either sides of surface of earth g goes on decreasing, hence period increases.

## What is the effect of pendulum clock if it is taken to a mountain?

On taking the pendulum to the top of a mountain, g will decrease, therefore, T will increase. The pendulum will take more time to complete one vibration, i.e., it will lose time.

IT IS SURPRISING:  Can you read messages on Michael Kors smartwatch?

## Will pendulum clock lose or gain time on hills or inside the mines?

On the top of a mountain, the value of g is less than on the surface of the earth. As T∝1√g , so the time period of pendulum clock increses. It means pendulum clock will take more time to complete one oscillation, i.e., it will be loosing time.

## What will be the effect on the time period of a simple pendulum when it is taken to a deep mine?

When a person goes from the surface of the earth to deep in the mine, the acceleration due to gravity decreases. Therefore, time period of oscillation of the simple pendulum increases deep in the mine.

## What are the factors on which time period of oscillation of simple pendulum does depends?

Answer: The time period of a simple pendulum depends upon the length of the pendulum, acceleration due to gravity and the temperature. it is directly proportional to the square root of length of pendulum (l) and inversely proportional to the square root of acceleration due to gravity (g).

## What would happen to the time period of a simple pendulum when mass of the bob is doubled?

Doubling the mass of the bob will half the period.

## Why does a pendulum clock gain time when taken from equator to the pole?

we know, acceleration due to gravity, g value at pole is greater than at equator. if it is taken to the poles g value increases. time period decreases so, the pendulum clock gains time. hence, if a pendulum clock gives correct time at the equator then, it gains time if it is taken to the poles.

## How does the time period get affected if a pendulum clock is taken to higher altitudes give the reason?

Will it gain or lose time? At high altitude, the value of acceleration due to gravity (g) is less than its value on the surface of the earth. So, it will take more time for the pendulum clock to complete one oscillation and hence, it will lose time. …

## When a pendulum clock is taken to the top of the mountain it becomes slow but a wrist watch controlled by a spring remains unaffected explain why?

When a clock controlled by a pendulum is taken from the plains to a mountain, it becomes slow but a wrist-watch controlled by a spring remains unaffected Due to decrease in the value of g at the mountain, the time period of the pendulum of the clock increases.

## Will a pendulum clock gain?

If a pendulum clock is taken to a mountain top, does it gain or lose time? When the pendulum is taken to the top of mountain, the value of ‘g’ will decrease and hence time period will increase. As the pendulum takes more time to complete one vibration, it will lose time.

## When a pendulum clock is taken from sea level?

Solution for problem 7Q Chapter 11

Why? The equation for pendulum motion is: As we gain altitude the value of constant of gravity ‘g’ decreases. If a pendulum clock which is accurate at sea level is taken to high altitude it will slow down.

## What will be the time loss or gain in day of a pendulum?

A gain of 2%of total time in a day.

IT IS SURPRISING:  Can you fix battery on Apple Watch?

## What will be the effect of a simple pendulum?

The time period of simple pendulum, T=2π√l/g, i.e., T∝1/√g. As the value of g is less at mountain then at plane, hence time period of simple pendulum will be more at mountain than at plane.

## What effect occurs on the frequency of a pendulum if it is taken from the earth’s surface to deep into a mine?

Frequency decreases.

With depth, the gravitational acceleration decreases. As the frequency of pendulum is proportional to square root of g, so with decrease in g, frequency f would decrease.